In the C standard library, the strxfrm()
function is used to transform a string into a form suitable for comparison based on specific locale settings (according to the current locale rules), allowing subsequent comparisons using strcmp()
.
strxfrm Function Header File
The header file for the strxfrm
function is <string.h>
. Before using the strxfrm
function, ensure that this header file is included in your C code:
#include <string.h>
strxfrm Function Prototype
size_t strxfrm(char * restrict s1,
const char * restrict s2,
size_t n);
The strxfrm
function transforms the string pointed to by s2
and places the resulting string into the array pointed to by s1
. The result array pointed to by s1
can hold at most n
characters, including the terminating '\0'
. If n
is 0
, s1
can be a null pointer. Behavior is undefined if copying occurs between overlapping objects.
Parameter Description
s1
: Pointer to the destination string, used to store the transformed string.s2
: Pointer to the source string, which needs to be transformed.n
: Size of the destination buffer, indicating the maximum number of characterss1
can store.
Return Value
The strxfrm
function returns the length of the transformed string (excluding the terminating '\0'
). If the returned value is n
or greater than n
, the content pointed to by s1
is undefined.
strxfrm Example Code
Due to the lack of sufficient locale types in the system, the transformation effects of this function cannot be demonstrated directly. This example only illustrates the usage of strxfrm
;
Typically, appropriate memory can be allocated by calling strxfrm()
twice. The first call uses n=0
to determine the required buffer size.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main() {
const char *src = "perfcode.com";
// Use n = 0, +1 to account for '\0'
size_t size = strxfrm(NULL, src, 0) + 1;
char* buffer;
buffer = (char*)malloc(size);
if(buffer == NULL){
// Memory allocation failed
return -1;
}
strxfrm(buffer, src, size);
printf("%s\n",buffer);
free(buffer);
return 0;
}